Hence we see that the equation of the required conic is A = x2+yi + zi + w2a 2yz a 2zxa 2xy a 2xwa 2ywa 2zvj = 0. ... of the four faces ; and then in each face, by lines drawn from the vertices of the face, project the point in that face uponanbsp;...

Title | : | Mathematical questions and solutions in continuation of the mathematical columns of "the Educational times" |

Author | : | |

Publisher | : | - 1865 |

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