Hence we see that the equation of the required conic is A = xi+y* + zi + wia 2yz a 2zxa 2xy a 2xwa 2ywa 2zw = 0. ... of the four faces ; and then in each face, by lines drawn from the vertices of the face, project the point in that face upon the anbsp;...
|Title||:||Mathematical questions with their solutions, from the "Educational times"...|
|Author||:||W. J. C. Miller, D. Biddle|