This edition is a specially designed self-study aid to help you get the most from the text and to effectively prepare for tests.Molar mass: C: 6x 12.01 = 72.06 g H: 12 x 1.008 = 12.096 g O: 6x16.00 = 96.00 p molar mass = 180.156 g glucose **(Note: We retain all ... 6.71% H 180.156 g glucose Mass percent of O= a r^T^T x 100% = 53.29% O ^ 180.156 g glucose Does the Answer Make Sense? ... in potassium ferricyanide, K3Fe(CN), Solution Using the same strategy as in the previous example, 54 Chapter 3 - Stoichiometry.
|Title||:||Study guide for Chemistry, third edition [by] Steven S. Zumdahl|
|Author||:||Paul B Kelter, Steven S. Zumdahl|
|Publisher||:||D C Heath & Co - 1993-06-01|